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Byju's Answer
Standard XI
Mathematics
Method of Intervals
The maximum v...
Question
The maximum value of
y
=
|
x
−
4
|
−
|
x
−
7
|
is
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Solution
y
=
|
x
−
4
|
−
|
x
−
7
|
Here the turning points are
4
,
7
y
=
⎧
⎨
⎩
−
(
x
−
4
)
+
(
x
−
7
)
x
<
4
(
x
−
4
)
+
(
x
−
7
)
4
≤
x
<
7
(
x
−
4
)
−
(
x
−
7
)
x
≥
7
⇒
y
=
⎧
⎨
⎩
−
3
x
<
4
2
x
−
11
4
≤
x
<
7
3
x
≥
7
Hence, the maximum value is
3
.
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Method of Intervals
Standard XI Mathematics
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