The maximum velocity and the maximum acceleration of a body moving in a

simple harmonic oscillator are 2 m/s and 4 m/ $s^{2}$ . Then angular velocity will be

[Pb. PMT 1998; MH CET 1999, 2003]

3 rad/sec

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0.5 rad/sec

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1 rad/sec

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2 rad/sec

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Solution

The correct option is D
2 rad/sec

$v_{m a x} = a ω a n d A_{m a x} = a ω^{2} \Rightarrow ω = \frac{A_{m a x}}{v_{m a x}} = \frac{4}{2} = 2 r a d / s e c$

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The maximum velocity and the maximum acceleration of a body moving in a simple harmonic oscillator are 2 m/s and 4 m/s2. Then angular velocity will be [Pb. PMT 1998; MH CET 1999, 2003]

The correct option is D 2 rad/sec vmax=aω and Amax=aω2⇒ω=Amaxvmax=42=2rad/sec

The maximum velocity and the maximum acceleration of a body moving in a

simple harmonic oscillator are 2 m/s and 4 m/ $s^{2}$ . Then angular velocity will be

[Pb. PMT 1998; MH CET 1999, 2003]

The correct option is D
2 rad/sec

$v_{m a x} = a ω a n d A_{m a x} = a ω^{2} \Rightarrow ω = \frac{A_{m a x}}{v_{m a x}} = \frac{4}{2} = 2 r a d / s e c$