The maximum wavelength of radiation that can produce photo-electric effect in a certain metal is $200 n m$ . The maximum kinetic energy acquired by electron due to radiation of wavelength $100 n m$ will be :

12.4 e V

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6.2 e V

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100 e V

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200 e V

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Solution

The correct option is A $6.2 e V$
From photoelectric equation , kinetic energy :

$K = h c (\frac{1}{λ} - \frac{1}{λ_{0}})$

$= \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{1.6 \times 10^{- 19}} \times (\frac{1}{100 \times 10^{-} 9} - \frac{1}{200 \times 10^{-} 9}) e V$

$= 6.2 e V$

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The maximum wavelength of radiation that can produce photo-electric effect in a certain metal is 200nm. The maximum kinetic energy acquired by electron due to radiation of wavelength 100nm will be :

The correct option is A 6.2eVFrom photoelectric equation , kinetic energy :K=hc(1λ−1λ0)=6.6×10−34×3×1081.6×10−19×(1100×10−9−1200×10−9)eV=6.2eV

The maximum wavelength of radiation that can produce photo-electric effect in a certain metal is $200 n m$ . The maximum kinetic energy acquired by electron due to radiation of wavelength $100 n m$ will be :

The correct option is A $6.2 e V$
From photoelectric equation , kinetic energy :

$K = h c (\frac{1}{λ} - \frac{1}{λ_{0}})$

$= \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{1.6 \times 10^{- 19}} \times (\frac{1}{100 \times 10^{-} 9} - \frac{1}{200 \times 10^{-} 9}) e V$

$= 6.2 e V$