The maximum wavelength of radiation that can produce photoelectric effect in a certain metal is 200 nm. The maximum kinetic energy acquired by electron due to radiation of wavelength 100 nm will be

12.4 eV

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6.2 eV

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100 eV

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200 eV

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Solution

The correct option is B
6.2 eV

$K_{m a x} (e V) = 12375 [\frac{1}{λ (\circ A)} - \frac{1}{λ_{0} (\circ A)}]$
$= 12375 [\frac{1}{1000} - \frac{1}{2000}] = 6.2 e V$

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The maximum wavelength of radiation that can produce photoelectric effect in a certain metal is 200 nm. The maximum kinetic energy acquired by electron due to radiation of wavelength 100 nm will be

The correct option is B 6.2 eV Kmax(eV)=12375[1λ(∘A)−1λ0(∘A)] =12375[11000−12000]=6.2 eV

The correct option is B
6.2 eV

$K_{m a x} (e V) = 12375 [\frac{1}{λ (\circ A)} - \frac{1}{λ_{0} (\circ A)}]$
$= 12375 [\frac{1}{1000} - \frac{1}{2000}] = 6.2 e V$