You visited us 1 times! Enjoying our articles? Unlock Full Access!

Nernst Equation

The maximum w...

Question

The maximum work that can be obtained from the cell
$A l | A l^{3 +} (0.1 M) | | F e^{2 +} (0.2 M) | F e$ is:

[Given : $E_{A l^{3 +} / A l}^{o} = - 1.66$ V and $E_{F e^{2 +} / F e}^{o} = - 0.44 V$ ]

605.8 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

505.8 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

705.8 kJ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

905.8 kJ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 705.8 kJ
The standard emf of the cell is $E_{c e l l}^{0} = E_{R}^{0} - E_{L}^{0}$

$= - 0.44 V - (- 1.66 V)$

$= 1.22 V$

The emf of the cell is $E_{c e l l} = E_{c e l l}^{0} - \frac{0.0592}{n} log \frac{{⌊ {A l}^{3 +} ⌋}^{2}}{{⌊ {F e}^{2 +} ⌋}^{3}}$

$= 1.22 V - \frac{0.0592}{6} log \frac{{(0.1)}^{2}}{{(0.2)}^{3}}$

$= 1.219 V .$

The maximum work that can be obtained from this cell is $W_{m a x} = - n F E_{c e l l} = - 6 \times 96500 \times 1.219$

$= - 705830 J = - 705.8 k J .$

Hence, the correct option is $C$

Suggest Corrections

Similar questions

E_{F e 2 + | F e}^{o} = - 0.44 V; E_{F e^{2 +} | F e^{3 +}}^{o} = - 0.77 V

F e^{2 +}, F e^{3 +}

F e

E_{F e^{2 +} / F e}^{o} = - 0.44 V, E_{F e^{2 +} / F e^{3 +}}^{o} = - 0.77 V

F e^{2 +}, F e^{3 +}

F e

F e^{2 +} (a q) + 2 e^{-} \to F e (s)

E^{⊖} = - 0.44 V

A l^{3 +} + 3 e^{-} \to A l (s)

E^{⊖} = - 1.66 V

B r^{2 +} 2 e^{-} \to 2 B r^{⊖} (a q)

E^{⊖} = - 1.08 V

F e | F e^{2 +} (0.2 M)

E_{(F e^{2 +} | F e)}^{⊖} = - 0.44 V

(E^{o})

F e^{3 +} \to F e

F e^{2 +} + 2 e^{-} \to F e; E_{F e^{2 +} / F e}^{o} = - 0.47 V

F e^{3 +} + e^{-} \to F e^{2 +}; E_{F e^{3} / F e^{2 +}}^{o} = + 0.77 V

Join BYJU'S Learning Program