The mean age of a combined group of men and women is $25$ yrs. If mean age of men is $26$ and that of women is $21,$ then percentage of men and women in the group. is:

60, 40

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80, 20

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20, 80

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30, 70

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Solution

The correct option is C $80, 20$
Let there be $x %$ of men.

Mean $= \frac{26 x + 21 (100 - x)}{100} = 25$

$26 x - 21 x + 2100 = 2500$

$5 x = 400 \Rightarrow x = 80$

Hence there are $80 %$ of men and

$20 %$ of women in the group.

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The mean age of a combined group of men and women is 25 yrs. If mean age of men is 26 and that of women is 21, then percentage of men and women in the group. is:

The correct option is C 80,20Let there be x% of men.Mean =26x+21(100−x)100=2526x−21x+2100=25005x=400⇒x=80Hence there are 80% of men and 20% of women in the group.

The mean age of a combined group of men and women is $25$ yrs. If mean age of men is $26$ and that of women is $21,$ then percentage of men and women in the group. is:

The correct option is C $80, 20$
Let there be $x %$ of men.

Mean $= \frac{26 x + 21 (100 - x)}{100} = 25$

$26 x - 21 x + 2100 = 2500$

$5 x = 400 \Rightarrow x = 80$

Hence there are $80 %$ of men and

$20 %$ of women in the group.