The mean of the values 0,1,2,………,n having corresponding weight nC0,nC1,nC2,…………nCn, respectively is
A
2nn+1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2n+1n(n+1)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
n+12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
n2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is Dn2 ¯¯¯x=0.1+1.nC1+2.nC2.+3.nC3+n.nCn1+nC1+nC2+..........+nCn =n∑r=0r.nCrn∑r=0=n∑r=1r.nrn−1Cr−1n∑r=0nCr==nn∑r=1n−1Cr−1n∑r=0nCr =n.2n−12n=n2