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Byju's Answer
Standard IX
Mathematics
Mathematical Expression for Mean
The mean of v...
Question
The mean of values 1,
1
2
,
1
3
,
.
.
.
.
.
1
n
which have frequencies 1, 2, 3, ...... n resp., is
A
2
n
+
1
3
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B
2
n
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C
n
+
1
2
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D
2
n
+
1
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Solution
The correct option is
C
2
n
+
1
Required mean
=
∑
x
i
f
i
∑
f
i
=
1
+
1
+
1
+
.
.
.
.
.
.
.
.
.
.
.
.
n times
1
+
2
+
3
+
4............
+
n
=
n
n
(
n
+
1
)
/
2
=
2
n
+
1
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0
Similar questions
Q.
The value of
lim
n
→
∞
(
n
(
n
+
1
)
√
2
n
+
1
+
n
(
n
+
2
)
√
2
(
2
n
+
2
)
+
n
(
n
+
3
)
√
3
(
2
n
+
3
)
.
.
.
.
.
+
1
2
n
√
3
)
is
Q.
The variate of a distribution takes the values
1
,
2
,
3
,
.
.
.
n
with frequencies
n
,
n
−
1
,
n
−
2
,
.
.
.
3
,
2
,
1.
then mean value of the distribution is
Q.
If a variable takes values
0
,
1
,
2
,
3
,
.
.
.
,
n
with frequencies
1
,
C
(
n
,
1
)
,
C
(
n
,
2
)
,
C
(
n
,
3
)
,
.
.
.
,
C
(
n
,
n
)
respectively, then the arithmetic mean is
Q.
Prove that
1
−
2
n
+
2
n
(
2
n
−
1
)
2
!
−
2
n
(
2
n
−
1
)
(
2
n
−
1
)
3
!
+
.
.
.
+
(
−
1
)
n
−
1
2
n
(
n
−
1
)
.
.
.
(
n
+
2
)
(
n
−
1
)
=
(
−
1
)
n
+
1
(
2
n
)
2
(
n
!
)
2
,
where n is a + ive integer.
Q.
If
2
n
C
2
+
2
n
C
4
+
2
n
C
6
+
⋯
+
2
n
C
2
n
=
511
, then absolue value of
n
C
0
−
n
C
1
3
1
+
n
C
2
3
2
+
⋯
+
(
−
1
)
n
n
c
n
3
n
is
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