Let a , b are the numbers.
since mean root is 28,
√(ab) = 28.
so, ab= 784
==> a = 784/b --(1)
Third propotion is 224
so , a, b , 224 are in propotion.
therefore, (a/b) = (b/224)
cross multiplying,
so , a× 224 = b^2 -->(2)
substitute (2) in (1)
(784/b)× 224 =b^2
therefore, (784×224) = b^3
therefore,b^3 = 175616
factorising,we get b= 56.
now substitute value of b in (1) to get a
a= 784/56 = 14.
sothe numbers are 14 & 56