The mean score of a person is 30 in 'n' exams. If he would have scored six marks extra in each of the first (n-1) exams, his mean score would have been 35. Find the number of exams.

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Solution

The correct option is D
6

Case - 1: Mean = 30
So, total marks score in "n" exams = 30n.

Case - 2: Mean = 35
So, total marks score in "n" exams = 35n.

Given: he scored 6 marks more in each of the (n-1) exams.
So, 30n + 6(n-1) = 35n
$\Rightarrow$ 6n-6 = 5n
$\Rightarrow$ n = 6.

Or, The number of exams = 6.

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The mean score of a person is 30 in 'n' exams. If he would have scored six marks extra in each of the first (n-1) exams, his mean score would have been 35. Find the number of exams.

The correct option is D 6Case - 1: Mean = 30 So, total marks score in "n" exams = 30n. Case - 2: Mean = 35 So, total marks score in "n" exams = 35n. Given: he scored 6 marks more in each of the (n-1) exams. So, 30n + 6(n-1) = 35n ⇒ 6n-6 = 5n ⇒ n = 6. Or, The number of exams = 6.