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Question

the measure of an angle is 6 times its component is 12 degree less than twice in supplement is

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Solution

Let the measure of an angle is x°.Measure of its complement = 90°-xmeasure of its supplement = 180°-xNow, according to question :690°-x = 2180°-x - 12°540° - 6x = 360° - 2x - 12°540° - 6x = 348° - 2x4x = 192°x = 48°So, required angle is 48°

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