Question

The measure of an angle of a parallelogram is ${70}^0$. Its remaining angles are:

• A. ${110}^0,{110}^0\text{and}{70}^0$
• B. ${110}^0,{70}^0\text{and}{120}^0$
• C. ${110}^0,{80}^0\text{and}{120}^0$
• D. ${90}^0,{70}^0\text{and}{120}^0$

Answer 1

The correct option is A ${110}^0,{110}^0\text{and}{70}^0$

Let $\angle A,\angle B,\angle C,\angle D$ be the four angles of the parallelogram ABCD, Such that $\angle B$ and $\angle D$ are opposite angles and also $\angle A$ and $\angle C$ are the opposite angles.

Let $\angle A={70}^o$, then $\angle C={70}^o$ {opposite angles are equal}

Angle adjacent to $\angle A=\angle D={180}^o-{70}^o$

$={110}^o$

Also, $\angle D=\angle B={110}^o$ {Opposite angles}

$Soanglesare{70}^{\circ },{110}^{\circ },{70}^{\circ },{110}^{\circ }\left(completeset\right)$