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Standard XII

Chemistry

Dalton's Law of Partial Pressures

The measured ...

Question

The measured density at $N T P$ of a gaseous sample of a compound was found to be $1.78 g / L$ . What is the weight of $1 m o l e$ of the gaseous sample?

45.6 g

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39.9 g

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28.25 g

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None of these

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Solution

The correct option is D None of these
$1.78 g$ of gas $\to$ 1lt at $N T P$
$x g r a m \to 39.9 g$
$x = 1.789 \times 39.9$
$x = 71 g$
so it is iron sulphate,which is having $70 g$ of molecular weight.
conclusion: hence the answer is option(D) None of these.

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The measured density at NTP of a gaseous sample of a compound was found to be 1.78 g/L. What is the weight of 1 mole of the gaseous sample?

The correct option is D None of these1.78g of gas→ 1lt at NTP xgram→39.9g x=1.789×39.9 x=71gso it is iron sulphate,which is having 70g of molecular weight.conclusion: hence the answer is option(D) None of these.

The measured density at $N T P$ of a gaseous sample of a compound was found to be $1.78 g / L$ . What is the weight of $1 m o l e$ of the gaseous sample?

The correct option is D None of these
$1.78 g$ of gas $\to$ 1lt at $N T P$
$x g r a m \to 39.9 g$
$x = 1.789 \times 39.9$
$x = 71 g$
so it is iron sulphate,which is having $70 g$ of molecular weight.
conclusion: hence the answer is option(D) None of these.