The measures of any godown are 60 m -25 m - 10 m- How many maximum wooden crate can be put in side the store of size 1-5 m -1-25 m -0-5 m-

According to the problem the volume of the grown =60×25× 10=15,000 cubic meter.And the volume of wooden crate =1.5×1.25×0.5=0.9375 cubic meter.So, m ...

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Standard VIII

Mathematics

Cubes Relation with Cube Numbers

The measures ...

Question

The measures of any godown are $60$ m $\times 25$ m $\times 10$ m. How many maximum wooden crate can be put in side the store of size $1.5$ m $\times 1.25$ m $\times 0.5$ m?

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Solution

According to the problem the volume of the grown $= 60 \times 25 \times 10 = 15, 000$ cubic meter.
And the volume of wooden crate $= 1.5 \times 1.25 \times 0.5 = 0.9375$ cubic meter.
So, maximum number of crate required $= \frac{15, 000}{0.9375} = 16, 000$ .

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The measures of any godown are 60 m ×25 m ×10 m. How many maximum wooden crate can be put in side the store of size 1.5 m ×1.25 m ×0.5 m?

According to the problem the volume of the grown =60×25×10=15,000 cubic meter.And the volume of wooden crate =1.5×1.25×0.5=0.9375 cubic meter.So, maximum number of crate required =15,0000.9375=16,000.

The measures of any godown are $60$ m $\times 25$ m $\times 10$ m. How many maximum wooden crate can be put in side the store of size $1.5$ m $\times 1.25$ m $\times 0.5$ m?

According to the problem the volume of the grown $= 60 \times 25 \times 10 = 15, 000$ cubic meter.
And the volume of wooden crate $= 1.5 \times 1.25 \times 0.5 = 0.9375$ cubic meter.
So, maximum number of crate required $= \frac{15, 000}{0.9375} = 16, 000$ .