The median AD of ΔABC meets BC at D. The internal bisectors of ∠ADB and ∠ADC meet AB and AC at E and F respectively. Then EF:
Question 28
In ΔABC, AD is the bisector of ∠A meeting BC at D, CF⊥AB and E is the mid-point of AC. Then, median of the triangle is
a) AD b) BE c) FC d) DE