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Question

The median for the data is :

IQ60−7070−8080−9090−100100−110110−120120−130No. of pupils2351614137


A

102.86

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B

98.46

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C

97.47

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D

103.26

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Solution

The correct option is A

102.86


n = 60

The median for grouped data is given by n2 = 602 = 30th Observation

Class IntervalFrequencyCumulative Frequency607022708035809051090100162610011014401101201353120130760

As we can see from the table ,

The 30th observation lies in the range 100-110

There are 14 values in this range.

Taking the step jump method we get :

IntervalNo.ofvalues = 57 = 0.7 approximately

If we start jumping from 100 we get :

100+0.7 , 100 + 1.4 , 100 + 2.1 , 100 + 2.8 , 100 + 3.5 and so on.... for this interval

The 30th Observation will lie between 100 + 2.8 and 100 + 3.5 (between 4th and 5th)

The 30th Observation = 102.8+103.52 = 103.15

The median is 103.15


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