Question

The median of $21$ observations is $40$. If each observation, greater than the median are increased by $6$, then the median of the observations will be

• A. $40$
• B. $46$
• C. $46+\frac{40}{21}$
• D. $46-\frac{40}{21}$

Answer 1

Answer: (A)

$40$

We know median of a arranged distribution is the term which middle most. So if observation greater than median is increased then it won't affect the relative position of the middle observation. Hence median will remain same.