The median of the observations $30, 91, 0, 64, 42, 80, 30, 5, 117, 71$ is __________.

52

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51

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53

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52.5

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Solution

The correct option is B $53$
Arranging the given numbers in ascending order
$0, 5, 30, 30, 42, 64, 71, 80, 91, 117$
Median of the above numbers is:
$= \frac{42 + 64}{2}$
$= \frac{106}{2} = 53$

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(2^{51} + 2^{52} + 2^{53} + 2^{54} + 2^{55})

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