Question

The medians AL, BM and CN of a $\Delta ABC$ intersect at P. If AL = 5, then the length of AP is

• A. $\frac{5}{13}$
• B. $\frac{5}{4}$
• C. $\frac{15}{2}$
• D. $\frac{10}{3}$

Answer 1

Answer: (D)

$\frac{10}{3}$

The centroid of the triangle divides the median in the ratio of 2:1
Thus, $\frac{AP}{PL}=2:1$
Therefore, AP = $\frac{2}{3}AL$ = $\frac{2}{3}\left(5\right)$ = $\frac{10}{3}$