Question

The melting point of a solid is $200K$ and its latent heat of fusion is $400calmo{l}^{-1}$. The entropy change for the fusion of 1 mole of the solid $\left(incal{K}^{-1}\right)$ at the same temperature would be:

• A. $800$
• B. $2$
• C. $0.2$
• D. $80$

Answer 1

Answer: (B)

$2$

As we know,

$\Delta S=\frac{q}{T}$

$=400/200$

$=2$