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Lattice Energy

The melting p...

Question

The melting point of $M g C l_{2}$ is greater than that of $B a C l_{2}$ . Give reason?

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Solution

The melting point of ${M g C l}_{2}$ is greater than ${B a C l}_{2}$ is because as we go down the group atomic size increases and its easy to break bonds between bond $C l$ than in between $M g$ and $C l$ .

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Similar questions

B e C l_{2}, M g C l_{2}, C a C l_{2}, S r C l_{2}

B a C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e C l_{2} < M g C l_{2} < C a C l_{2} < S r C l_{2} < B a C l_{2} < R a C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

A g I

A g F

I^{-}

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B a C l_{2}

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A l^{3 +} (a q) > M g^{2 +} (a q) > N a^{+} (a q)

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