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Question

The metal salt A is blue in colour. When salt A is heated strongly over a burner, then a substance B is eliminated and a white powder C is left behind. When a few drops of a liquid D are added to powder C, it becomes blue again. What could be A, B, C and D?


Solution

Copper sulphate pentahydrate (CuSO4.5H2O) crystals (salt A) are blue in colour; intense heating causes loss of all water (substance B) and leaves white anhydrous copper sulphate (salt C) behind.

CuSO4.5H2O A CuSO4 B +5H2O C 


Addition of a few drops of water (liquid D) turns the anhydrous copper sulphate into blue coloured copper sulphate pentahydrate. 

CuSO4 C+5H2O D CuSO4.5H2O A 


Chemistry
Science for Tenth Class - Part II - Chemistry
Standard X

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