The metal salt A is in blue colour. When salt A is heated strongly over a burner then a substance B present in it is eliminated and a white powder C is left behind when a few drops of a liquid D are added to powder C, it becomes blue again. Write the chemical equations involved.

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Solution

A must be $C u S O_{4} \cdot 5 H_{2} O$ which is blue in colour and $B$ must be $H_{2} O$ and $C$ is $C u S O_{4}$ that is anhydrous. As shown in above equation.

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The metal salt A is in blue colour. When salt A is heated strongly over a burner then a substance B present in it is eliminated and a white powder C is left behind when a few drops of a liquid D are added to powder C, it becomes blue again. Write the chemical equations involved.

A must be CuSO4⋅5H2O which is blue in colour and B must be H2O and C is CuSO4 that is anhydrous. As shown in above equation.

A must be $C u S O_{4} \cdot 5 H_{2} O$ which is blue in colour and $B$ must be $H_{2} O$ and $C$ is $C u S O_{4}$ that is anhydrous. As shown in above equation.