The metallic oxide of a divalent metal which on thermal decomposition liberates oxygen is:

C O_{2}

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P_{2} O_{5}

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H g O

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N_{2} O

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Solution

The correct option is C $H g O$
Mercuric Oxide on thermal decomposition gives $H g$ and $O_{2}$
$2 H g O$ $\to$ $2 H g + O_{2} ↑$

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