The mid point of the line joining any two point $(6, 7)$ and $(2, 9)$

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Solution

Using the section formula, if a point $(x, y)$ divides the line joining the points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ in the ratio $m : n$ , then
$(x, y) = (\frac{m x_{2} + n x_{1}}{m + n}, \frac{m y_{2} + n y_{1}}{m + n})$
So, $m = 1$ and $n = 1$
$∴$ the mid point of the line joining any two point $(6, 7)$ and $(2, 9)$ is $(\frac{6 + 2}{2}, \frac{7 + 9}{2}) = (4, 8)$ .

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The mid point of the line joining any two point (6,7) and (2,9)

Using the section formula, if a point (x,y) divides the line joining the points (x1,y1) and (x2,y2) in the ratio m:n, then (x,y)=(mx2+nx1m+n,my2+ny1m+n)So, m=1 and n=1∴ the mid point of the line joining any two point (6,7) and (2,9) is (6+22,7+92)=(4,8).

The mid point of the line joining any two point $(6, 7)$ and $(2, 9)$