Question

The mid points of the sides of a triangle ABC along with any of the vertices as the fourth point make a parallelogram of area equal to

• A. $ar\left(△ABC\right)$
  
• B. $\frac{1}{2}ar\left(△ABC\right)$
• C. $\frac{1}{3}ar\left(△ABC\right)$
  
• D. $\frac{1}{4}ar\left(△ABC\right)$
  

Answer 1

The correct option is B

$\frac{1}{2}ar\left(△ABC\right)$

If P, Q and R the midpoints of the sides of a$△ABC$, area of any parallelogram formed by the midpoints and one vertex of the given triangle has area $=\frac{1}{2}area△ABC$