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Question

The middle term in the expansion of (ba55ab)12 is:


A

12C6(b/a)3

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B

-12C6(b/a)3

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C

12C7(b5/a)

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D

-12C7(b5/a)

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Solution

The correct option is A

12C6(b/a)3


Middle term is T122+1=T6+1=12C6(ba5)126(5ab)6=12C6(ba)3


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