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Question

The middle term in the expansion of (x2+1x)n is 924x6. If n is even, then n is equal to

A
10
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B
12
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C
24
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D
6
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Solution

The correct option is B 12
Since, n is even.
The middle term =(n2+1)th term

T(n/2+1)= nCn/2(x2)n/2 (1x)n/2= nCn/2 xn/2
T(n/2+1)=924x6 (given)
xn/2=x6
n=12

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