The midpoint of the points on x + y = 4 and 4x + 3y - 10 = 0 which are at a distance of 4 units is the point of intersection of the two lines given.
True
We draw perpendicularfrom L2 to meet L1 at different points. Some of these perpendicular are going to be 1 unit. As we can see the length of the perpendicular is zero at the point of contact and it increases as we move on either side. We can see that there will be exactly two points which are at unit distance from L2. Let those points be P(x1,y1) and Q(x2,y2).