The minimum deviation produced by a hollow prism filled with a certain liquid to be 300. The light ray is also found to be refracted at angle 300. The refractive index of the liquid is
A
√32
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B
√3
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C
√2
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D
32
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Solution
The correct option is C√2 For minimum angle of deviation for a prism A=2r,∴A=60o Now μ=sin60+302sin602=sin45osin30o=1√2×21=√2