The minimum EMF required to carry out the electrolysis of CuO is Given - G - for the reaction is -827 kJ mol -1 A- 2-14 VB- 8-56 VC- 4-28 VD- 6-42 V

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Catalytic Hydrogenation

The minimum E...

Question

The minimum EMF required to carry out the electrolysis of CuO is ( Given ∆G^o for the reaction is - 827 kJ mol^-1)

2.14V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.42V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.28V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8.56V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

Δ G = - 827 k J {m o l}^{- 1}

O_{2}

{A l}_{2} O_{3}

(F = 96500 C {m o l}^{- 1})

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3}, Δ G = - 827 k J m o l^{- 1}

O_{2}

A l_{2} O_{3}

[F = 96500 C m o l^{- 1}]

Δ G

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3},

^{- 1}

O_{2}

A l_{2} O_{3}

On the basis of information available from the reaction

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3}, Δ G = - 827 k J . m o l^{- 1}

The minimum emf required to carry out the electrolysis of $A l_{2} O_{3}$ is:

$[F = 96500 C m o l^{- 1}]$

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3}, Δ G = - 827 {kJ mol}^{- 1}

O_{2}

A l_{2} O_{3}

Join BYJU'S Learning Program