The minimum EMF required to carry out the electrolysis of CuO is Given - G - for the reaction is -827 kJ mol -1 A- 2-14 VB- 8-56 VC- 4-28 VD- 6-42 V

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Catalytic Hydrogenation

The minimum E...

Question

The minimum EMF required to carry out the electrolysis of CuO is ( Given ∆G^o for the reaction is - 827 kJ mol^-1)

2.14V

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6.42V

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4.28V

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8.56V

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Δ G = - 827 k J {m o l}^{- 1}

O_{2}

{A l}_{2} O_{3}

(F = 96500 C {m o l}^{- 1})

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3}, Δ G = - 827 k J m o l^{- 1}

O_{2}

A l_{2} O_{3}

[F = 96500 C m o l^{- 1}]

Δ G

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3},

^{- 1}

O_{2}

A l_{2} O_{3}

On the basis of information available from the reaction

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3}, Δ G = - 827 k J . m o l^{- 1}

The minimum emf required to carry out the electrolysis of $A l_{2} O_{3}$ is:

$[F = 96500 C m o l^{- 1}]$

\frac{4}{3} A l + O_{2} \to \frac{2}{3} A l_{2} O_{3}, Δ G = - 827 {kJ mol}^{- 1}

O_{2}

A l_{2} O_{3}

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