The minimum equivalent conductance in fused state is shown by:

M g C l_{2}

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B e C l_{2}

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C a C l_{2}

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S r C l_{2}

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Solution

The correct option is B $B e C l_{2}$
On moving downward in a group, atomic size increases, and hence, covalent character decreases. Thus, $S r C l_{2}$ is most ionic among the given compound ie, it will give ion readily when is in a fused state. Hence, $S r C l_{2}$ exhibit the maximum value of equivalent conductance in a fused state.

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Similar questions

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e C l_{2} < M g C l_{2} < C a C l_{2} < S r C l_{2} < B a C l_{2} < R a C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

R a C l_{2} < B a C l_{2} < S r C l_{2} < C a C l_{2} < M g C l_{2} < B e C l_{2}

B e C l_{2}, M g C l_{2}, C a C l_{2}, S r C l_{2}

B e C l_{2}, M g C l_{2}, C a C l_{2}, S r C l_{2}

B a C l_{2}

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