Question

The minimum horizontal acceleration of the container, so that the pressure at point $A$ of the container becomes atmospheric is (the tank is of sufficient height) ?

• A. $\frac{2}{3}g$
• B. $\frac{4}{3}g$
• C. $\frac{4}{2}g$
• D. $\frac{3}{4}g$

Answer 1

The correct option is B $\frac{4}{3}g$

The finel liquid profile must be like

Now,

from volume conservation.

$b(3\times 2)=(\frac{1}{2}\times 3(2+x))b$

where,

$b\to$ the breath of container

So,

$\Rightarrow 2\left(6\right)=3(2+x)$

$\Rightarrow x=2m$

Now,

$\tan \theta =\frac{a}{g}$

$\Rightarrow \frac{2+x}{3}=\frac{a}{g}$

$\Rightarrow a=\frac{4g}{3}$