The minimum mass of sulphuric acid needed to dissolve 3 gm of magnesium carbonate is:

3.5 gm

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0.4 gm

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2.6 gm

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3 gm

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Solution

The correct option is A 3.5 gm
$M g C O_{3} + H_{2} S O_{4} \to M g S O_{4} + C O_{2} + H_{2} O$ 84 gm 98 gm

$84 g m M g C O_{3}$ needs = 98 gm $H_{2} S O_{4}$
$∴$ 1 gm $M g C O_{3}$ needs = $\frac{98}{84} g m H_{2} S O_{4}$
$3 g m M g S O_{4}$ needs $H_{2} S O_{4} = \frac{98}{84} \times 3 = 3.5 g m .$

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The minimum mass of sulphuric acid needed to dissolve 3 gm of magnesium carbonate is:

The correct option is A 3.5 gm MgCO3+H2SO4→MgSO4+CO2+H2O84 gm 98 gm 84 gm MgCO3 needs = 98 gm H2SO4 ∴ 1 gm MgCO3 needs = 9884 gm H2SO4 3 gm MgSO4 needs H2SO4=9884×3=3.5 gm.