The minimum mass of the mixture of A2 and B4 required to produce at least 1kg of each product is: (Given At. mass of A=10; At. mass of B=120) 5A2+2B4⟶2AB2+4A2B.
A
2120gm
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B
1060gm
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C
560gm
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D
1660gm
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Solution
The correct option is A2120gm Molar masses of AB2andA2B are 250 g/mol and 140 g/mole respectively. 1 kg of AB2 corresponds to 4 moles. It requires 10 mole A2 and 4 mole B4 respectively. 1 kg of A2B corresponds to 7.14 mole. It requires 8.9 mole A2 and 3.57 mole B4 respectively. Thus 10 mole A2 (200 g) and 4 mole B4 (1920 g) will produce atleast 1 kg of each product. The minimum mass of mixture required is 200g+1920g=2120g.