The minimum number of gates required to realise the expression $Z = D A B C + D ¯ ¯¯¯¯¯¯¯¯¯¯ ¯ A B C$ is

One

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Two

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Eight

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Five

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Solution

The correct option is A One
The given expression is same as $Z = D$ .
Hence, one gate is sufficient to realise this expression.

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f = (B + B C) (B + ¯ ¯¯ ¯ B C) (B + D)

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