Question

The minimum number of NOR gates required to implement$f=A(A+\overline{B})(A+\overline{B}+C)$ is equal to _______.

• A. 0

Answer 1

The correct option is A 0
Given, $f=A(A+\overline{B})(A+\overline{B}+C)$

$=(A.A+A\overline{B})(A+\overline{B}+C)$

$=A(1+\overline{B})(A+\overline{B}+C)$

$=(A.A+A.\overline{B}+AC)$

$=(A+A\overline{B}+AC)$

$=A(1+\overline{B}+C)=A$

$\therefore$ No gate is required for implementation of f i.e., 0