Question

The minimum number of plants to be screened to obtain a plant of the genotype $AabbCcDd$ from a cross between plants of genotypes $AaBbCcDd$ and $AABbCCDd$ is

• A. $8$
• B. $16$
• C. $32$
• D. $64$

Answer 1

The correct option is C $32$

Number of plants with particular genotype can be calculated by the formula 2${}^n$, where n is the number of heterozygous gene in the desired genotype.

Therefore, plants with genotype AabbCcDd = 2${}^3$ = 8.

Thus, the correct answer is option A.