The minimum value of $cos (cos x)$ is

0

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- cos 1

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cos 1

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- 1

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Solution

The correct options are
A $0$
C $cos 1$
We know, $- 1 \leq cos x \leq 1$
$\frac{π}{3} = 1.04$
Thus we can say,
$\frac{- π}{3} < cos x < \frac{π}{3}$
$cos 1 \leq cos (cos x) \leq 1$
Minimum value is $= cos 1$

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