The minimum wavelength of the X-rays produced accelerating potential is λ. If the accelerating potential is changed to 2V . then the minimum wavelength would become:
A
4λ
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B
2λ
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C
λ/2
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D
λ/4
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Solution
The correct option is Aλ/2 Energy of produced photon is E=eV and E=hcλ
V is accelrating potential.
So λ∝1V
so making V , 2 times will make lambda , 12 times i.e. λ/2