The minimum wavelength of x-rays emitted from x-ray machine operating at an accelerating potential of V volts is

\frac{h c}{e V}

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\frac{V c}{e h}

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\frac{e h}{V c}

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\frac{e V}{h c}

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Solution

The correct option is A $\frac{h c}{e V}$
$E_{m a x} = h v_{m a x} = e V$
$\Rightarrow \frac{h c}{λ_{m i n}} = e V$

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Similar questions

The minimum wavelength of X-rays emitted from an X-ray tube operating at a voltage of $10^{4} V$ is roughly equal to

12400 V

h c = 1240 e V - n m

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