The modulus of (1 + i) (1 + 2i) (1 + 3i) is equal to

\sqrt{1} 0

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\sqrt{5}

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Solution

The correct option is D 10
$| (1 + i) (1 + 2 i) (1 + 3 i) |$ = $| 1 + i | | 1 + 2 i | | 1 + 3 i |$ ( $∵ | Z_{1} Z_{2} | = | Z_{1} | | Z_{2} |$ )
$= \sqrt{2} \cdot \sqrt{5} \cdot \sqrt{10}$
$∴ | (1 + i) (1 + 2 i) (1 + 3 i) | = 10$
Hence, option D.

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