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Question

The modulus of (1+i)(3+4i)=

A
50
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B
25
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C
10
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D
102
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Solution

The correct option is A 50
z1,z2 being two complex numbers,
|z1.z2|=|z1|.|z2|
|(1+i)(3+4i)|=|1+i||3+4i|
=12+12×32+42
=225
=50

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