The molal depression constant for water is ${1.86}^{o} C$ .The freezing point of a $0.05$ molal solution of a non-electrolyte in water is:

- {1.86}^{o} C

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- {0.93}^{o} C

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- {0.093}^{o} C

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{0.93}^{o} C

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Solution

The correct option is C $- {0.093}^{o} C$
$Δ T_{f} = K_{f} \times M o l a l i t y$

$= 1.86 \times 0.05$

$= 0.093$

Thus, freezing point $= 0 - 0.093$
$= - 0.093$

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