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Question

The molality of a sulphuric acid solution is 0.2 mol/kg. Calculate the total weight of the solution having 1000 g, of solvent:-

A
1000 g
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B
1098.6 g
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C
980.4 g
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D
1019.6 g
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Solution

The correct option is D 1019.6 g
Given, molality (m) = 0.2 mol/kg
weight of solvent = 1000 g
Since it is a sulphuric acid (H2SO4) solution weight of solute =0.2×98=19.6 g
Total weight of solution will be =1000+19.6=1019.6 g

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