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Solubility Product

The molar con...

Question

The molar concentration of 64g of $S O_{2}$ in a four litre flask would be:

A

2

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B

1

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C

5

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D

0.25

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Solution

The correct option is D 0.25
Molar concentration of $64 g$ of ${S O}_{2}$ in $4 L$ flask.
Molarity=No. of moles of solute dissolved in a litre of solution.
$M = \frac{m o l e s o f s o l u t e}{V o l u m e i n l i t r e} = m o l / l i t r e (M) n o . o f m o l e s = \frac{G i v e n m a s s}{G r a m M o l e c u l e M a s s} = \frac{m}{G M M} {S O}_{2} = S + 20 = 32 + 2 \times 16 = 32 + 32 G M M = 64 g M = \frac{1 m o l e}{4 L} = 0.25 m o l / L M = 0.25 M$

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