The molar conductances of HCl- NaCl and CH3COONa are 426- 126 91 -1cm2mol-1 respectively- The molar conductances of CH3COOH is -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equivalent, Molar Conductivity and Cell Constant

The molar con...

Question

The molar conductances of HCl, NaCl and $C H_{3} C O O N a$ are 426, 126 91 $Ω^{- 1} c m^{2} m o l^{- 1}$ respectively. The molar conductances of $C H_{3} C O O H$ is :

561 Ω^{- 1} c m^{2} m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

391 Ω^{- 1} c m^{2} m o l^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

261 Ω^{- 1} c m^{2} m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

612 Ω^{- 1} c m^{2} m o l^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $391 Ω^{- 1} c m^{2} m o l^{- 1}$
According to kohlrausch law of independent migration of ions, the molar conductivity of an electrolyte at infinite dilution is equal to the sum of the contributions of the molar conductivites of its ions.
Hence,
$Λ_{H O A c}^{\infty} = Λ_{H +}^{\infty} + Λ_{A c O -}^{\infty} = Λ_{N a O A c}^{\infty} + Λ_{H C l}^{\infty} - Λ_{N a C l}^{\infty}$
Substitute the values in the above equation.
$Λ_{H O A c}^{\infty} = 91 + 426 - 126 = 391 Ω^{- 1} {c m}^{2} {m o l}^{- 1}$
Hence, option B is correct.

Suggest Corrections

Similar questions

The molar conductances of NaCl, HCl and CH₃COONa at infinite dilution are 126.45, 426.16 and 91 ohm^-1 cm² mol^-1 respectively. The molar conductance of CH₃COOH at infinite dilution is

Q. Given the limiting molar conductivity as

_{m}

(HCl)

= 425.9 Ω^{- 1} c m^{2} m o l^{- 1}

_{m}

(NaCl)

= 126.4 Ω^{- 1} c m^{2} m o l^{- 1}

_{m}

(CH3 COONa)

= 91 Ω^{- 1} c m^{2} m o l^{- 1}

The molar conductivity, at infinite dilution, of acetic acid (in

Ω^{- 1} c m^{2} m o l^{- 1}

) will be

Q. The molar conductivities are zero concentrations of

N H_{4} C l

,NaOH and NaCl are respectively

149.7 Ω^{- 1} c m^{2} m o l^{- 1}

248.1 Ω^{- 1} c m^{2} m o l^{- 1}

and

126.5 Ω^{- 1} c m^{2} m o l^{- 1}

. What is the molar conductivity of

N H_{4} O H

at zero concentration ?

Q. Given the limiting molar conductivity as

^0 m (H C l) = 425.9 Ω - 1 c m 2 m o l - 1

^0 m (N a C l) = 126.4 Ω - 1 c m 2 m o l - 1

^0 m (C H 3 C O O N a) = 91 Ω - 1 c m 2 m o l - 1

The molar conductivity, at infinite dilution, of acetic (in

Ω - 1 c m 2 m o l - 1

) will be:

Q. The molar conductances of

N a C l, H C l

and

C H_{3} C O O N a

at infinite dilution are

126.45, 426.16

and

91 o h m^{- 1} c m^{2} m o l^{- 1}

respectively. The molar conductance of

C H_{3} C O O H

at infinite dilution is:

Join BYJU'S Learning Program

The molar conductances of HCl, NaCl and CH3COONa are 426, 126 91 Ω−1cm2mol−1 respectively. The molar conductances of CH3COOH is :

The molar conductances of HCl, NaCl and $C H_{3} C O O N a$ are 426, 126 91 $Ω^{- 1} c m^{2} m o l^{- 1}$ respectively. The molar conductances of $C H_{3} C O O H$ is :