The molar conductances of NaCl,HCl and CH3COONa at infinite dilution are 126.45,426.16 and 91ohm−1cm2mol−1 respectively. The molar conductance of CH3COOH at infinite dilution is:
A
201.28ohm−1cm2mol−1
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B
390.71ohm−1cm2mol−1
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C
698.28ohm−1cm2mol−1
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D
540.48ohm−1cm2mol−1
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Solution
The correct option is B390.71ohm−1cm2mol−1 ΛNaCl=ΛNa++ΛCl−ΛHCl=ΛH++ΛCl−ΛCH3COONa=ΛNa++ΛCH3COO−Let,ΛNa+=x,ΛCl−=y,ΛH+=z,ΛCH3COO−=wGiven,x+y=126.45y+z=426.16x+w=91