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Question

The molar conductivities of HCl,NaCl,CH3COOH, and CH3COONa at infinite dilution follow the order.

A
HCl>CH3COOH>NaCl>CH3COONa
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B
CH3COONa>HCl>NaCl>CH3COOH
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C
HCl>NaCl>CH3COOH>CH3COONa
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D
CH3COOH>CH3COONa>HCl>NaCl
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Solution

The correct option is A HCl>CH3COOH>NaCl>CH3COONa
Since conductance of H+ is highest so molar conductivity of HCl will be highest and after that conductance of CH3COOH will come.

The order of molar conductivities: HCl>CH3COOH>NaCl>CH3COONa

Hence, option A is correct.

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