The molar conductivity of $0.1 M C H_{3} C O O H$ solution is $4 S c m^{2} m o l^{- 1}$ . What is the specific conductivity and resistivity of the solution.

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Solution

We know that $λ m = \frac{K}{C}$
$K = λ m C$
$\Rightarrow K = 4 S c m^{2} m o l^{- 1} \times 0.1 M$
$\Rightarrow 4 S c m^{2} m o l^{- 1} \times 0.1 m o l \times 10^{- 3} c m^{- 3}$
$K = 4 \times 10^{- 4} c m^{- 1}$
Hence, conductivity is $4 \times 10^{- 4} c m^{- 1}$
Resistivity $ρ = \frac{1}{K} = \frac{1}{4 \times 10^{- 4}} = 0.25 \times 10^{- 4} c m$

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